In một chuỗi trong càng ít ký tự riêng biệt càng tốt

27

Nhiệm vụ rất đơn giản: in The quick brown fox jumps over the lazy dogbằng cách sử dụng càng ít ký tự riêng biệt trong mã nguồn của bạn càng tốt.

print "The quick brown fox jumps over the lazy dog"có số điểm 29 ký tự, vì tất cả 26 chữ cái viết thường xuất hiện ít nhất một lần, cũng như chữ T, dấu cách và ký tự trích dẫn. Tuy nhiên, tôi chắc chắn rằng bạn có thể sáng tạo hơn thế!

Brainfuck, Whitespace và các ngôn ngữ tương tự (theo ý của tôi) không được phép. Ngắt dòng được tính là một ký tự. Mã có thể miễn là cần thiết. Tôi sẽ chấp nhận một giải pháp vào ngày 21 tháng 4, 11:59 PM EST. Trong trường hợp hòa, câu trả lời ngắn hơn sẽ được chấp nhận.

code-challenge 
— Fraxtil
nguồn
OP bạn có thể làm điều này thú vị hơn bằng cách yêu cầu người dùng viết chương trình lấy một chuỗi làm đầu vào và xuất ra một chương trình khác in chuỗi đầu vào với càng ít ký tự càng tốt.
— Soham Chowdhury
Là trường hợp đầu ra nhạy cảm?
— zzzzBov
@zzzzBov: vâng, chữ T hàng đầu cần là chữ hoa và mọi thứ khác chữ thường.
— Fraxtil
Chúng ta có thể tạo least-charactersmột tiêu chí và thẻ chính thức không, nhưcode-golf
— EAKAE
2
@EAKAE, có bao nhiêu câu hỏi khác nhau như thế này sẽ thực sự thú vị? Nhiều câu trả lời ở đây là các giải pháp chung có thể thực thi mã tùy ý.

Câu trả lời:

12

dc: 4 ký tự riêng biệt ( tổng cộng 384 375 363 361 360 350)

Một câu trả lời ngắn (nhưng cách xa nhất có thể, tôi vẫn đang làm việc với nó) chỉ sử dụng 4 ký tự riêng biệt và 384 tổng cộng 375 363 361 360 350, tôi hy vọng bạn sẽ thấy nó hoàn toàn tự giải thích:

11d1+ddd++d++dP+1+1+ddd1+ddddd1+dd1+1+ddd1+1+1+PP1d+d+d+d+d+P11+1+dP1d+d++P1d+d++PP1d+d+d++P1d+d+d+d+d+PP111dd1+1+1+PP1d+d+d++P11+1+P1d+d+d+d+d+P1d+d++P111P1d+d+d++ddd11+1+1+1+P1d+d+d+d+d+PP11+P1+1+1+dP1+1+1+dP1+1+1+dP1d+d+d+d+d+P111P1+1+1+P1+1+1+dddP11+1+1+dP1d+d+d+d+d+P1+1+P1+1+1+PP1d+d+d+d+d+P11+PP11dd+dd+d+++d1+PP1d+d+d+d+d+P1+1+1+dP111P1+1+1+P

Câu trả lời trước đó dài dòng hơn một chút (nó chứa 13916 1):

1111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111 11/P1111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/P1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 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11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/P111P1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111 11/P11111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111 11/P1111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P1111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/P11111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111P1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/11/P111 11/P

Ah, bạn chỉ cần yêu máy tính bàn đáng tin cậy của ole!

— Fors
nguồn
1
Vì bạn và Peter hiện đang bị ràng buộc với 4 ký tự mỗi ký tự, tôi đã cập nhật các quy tắc để nói rằng nếu đó vẫn là một ràng buộc khi thời hạn đến, tôi sẽ chấp nhận câu trả lời ngắn hơn. Như vậy, bạn có thể muốn xem xét làm những gì bạn mô tả trong đoạn cuối.
— Fraxtil
Một câu trả lời thực sự ngắn và tốt đẹp đang được tiến hành.
— Dành cho
22

Mã máy 64 bit của Intel cho Linux ở dạng nhị phân: 2 ký tự riêng biệt

01111111010001010100110001000110000000100000000100000001000000000000000000000000
00000000000000000000000000000000000000000000000000000010000000000011111000000000
00000001000000000000000000000000011110000000000001000000000000000000000000000000
00000000000000000100000000000000000000000000000000000000000000000000000000000000
00000000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000100000000000000001110000000000000000001000000000000000000000000
00000000000000000000000000000000000000010000000000000000000000000000010100000000
00000000000000000000000000000000000000000000000000000000000000000000000000000000
00000000000000000100000000000000000000000000000000000000000000000000000000000000
01000000000000000000000000000000000000000000000011001011000000000000000000000000
00000000000000000000000000000000110010110000000000000000000000000000000000000000
00000000000000000000000000000000001000000000000000000000000000000000000000000000
10111000000000010000000000000000000000001011111100000001000000000000000000000000
01001000101111101001111100000000010000000000000000000000000000000000000000000000
10111010001011000000000000000000000000000000111100000101101110000011110000000000
00000000000000001011111100000000000000000000000000000000000011110000010101010100
01101000011001010010000001110001011101010110100101100011011010110010000001100010
01110010011011110111011101101110001000000110011001101111011110000010000001101010
01110101011011010111000001110011001000000110111101110110011001010111001000100000
01110100011010000110010100100000011011000110000101111010011110010010000001100100
011011110110011100001010

Tôi từ chối viết lại nó trong unary.

— Fors
nguồn
7
Vì vậy, không có công cụ tiêu chuẩn nào để chuyển đổi nó thành một tệp thực thi và mã hóa tương tự có thể được áp dụng như nhau cho bất kỳ câu trả lời nào khác không?
— Peter Taylor
1
Nếu bạn từ chối gọi home.paulschou.net/tools/xlate là "công cụ tiêu chuẩn", thì không. Nhưng nó chắc chắn tồn tại khi thử thách này bắt đầu.
— Dành cho
2
Đây có thể được coi là mã nguồn, vì nó chỉ cần một công cụ duy nhất để trở thành mã máy.
— Fors
5
Mọi người không thể đánh giá cao nó vì điều đó ... Có lẽ họ đang đau mông?
— jdstankosky
20
Xin lỗi, nhưng tôi sẽ phải loại bỏ điều này vì lý do tương tự như lý do tại sao tôi không cho phép Brainfuck và Whitespace. Khi ngôn ngữ trong câu hỏi bị giới hạn ở một số lượng nhỏ ký tự (8 cho Brainfuck, 3 cho Whitespace, 2 cho bất kỳ biểu diễn nhị phân nào), nó có một lợi thế rõ ràng không công bằng so với các bài nộp khác.
— Fraxtil
19

Lua, 8 nhân vật riêng biệt

load"load\"load\\\"load\\\\\\\"load\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\5\50\\5\55\\\\0
\\5\50\\05\55\50\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50\\5\55\\5\50\\\\\\\\\\\\0\\5\
50\\05\05505\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50\\05\0550\\\\\\\\\\\\\\5\50\\5\55
\\\\\\5\50\\5\55\\\\5\\5\50\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\\\\\\
\\\05\\\\05\\5\50\\5\50\\\\\\\\\\\\0\\5\50\\05\0550\\5\50\\\\\\\\\\\\0\\5\50\\05
\0550\\\\\\5\50\\5\55\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\55\50\\\\\\\\\\\\
\\\\\\\\\\5\50\\5\55\\\\\\5\50\\5\55\\\\\\\\5\\\\\\5\50\\5\55\\\\\\\\\\\\\\5\50\
\5\55\\\\0\\5\50\\05\55\55\\\\\\\\\\\\0\\5\50\\05\05505\\\\\\5\55\\5\55\\\\\\\\\
\\\0\\5\50\\05\0550\55\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\55\50\\\\\\\\\\\
\\\\\\\5\55\\\\\\\\5\\\\5\\5\50\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50\\5\55\\5\50o\
\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50\\5\55\\5\55\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\5
0\\05\0550\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\55\50\\\\\\\\\\\\0\\5\50\\05
\0550\50o\\\\\\\\\\\\0\\5\50\\05\55\0500\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\0
5\55\50\\\\\\\\\\\\0\\5\50\\05\0550\\\\5\\5\50\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\5
0\\05\55\55\\\\\\\\\\\\0\\5\50\\05\0550\\5\55\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50
\\05\55\50\\\\\\\\\\\\\\5\50\\5\55\\\\0\\5\50\\05\0555\\\\\\\\\\\\\\\\\\\\\\\\05
\\\\0\\5\50\\05\55\50o\\\\\\\\\\\\\\\\\\\\\\5\50\\5\55\\\\\\5\50\\5\55\\\\\\\\5\
\\\5\\5\50\\\\\\\\\\\\0\\5\50\\05\0550\\\\\\5\50\\5\55\\\\\\\\\\\\\\5\50\\5\55\\
\\0\\5\50\\5\55\\5\50\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\55\50\\\\\\\\\\\\
\\5\50\\5\55\\\\\\5\50\\5\55\\\\5\\5\50\\\\\\\\\\\\0\\5\50\\05\0550\\5\50\\\\\\\
\\\\\0\\5\50\\05\0550\\\\\\5\50\\5\55\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\5
5\50la\\\\\\\\\\\\0\\5\50\\05\55\50\50\\\\\\\\\\\\0\\5\50\\05\55\50\\\\\\5\50\\5
\55\\\\\\\\\\\\\\\\\\\\\\\\05\\\\0\\5\50\\05\55\50do\\\\\\\\\\\\\\\\\\\\0\\5\50\
\05\0550\\\\\\\\5\\\\\\5\50\\5\55\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\
"\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\"\\\\\\\"\\\\\\\"\\\\\\\"\\\"\\\"\\\"\"\"\""""

Tất cả các ký tự dòng mới phải được xóa khỏi mã này để có được một dòng có độ dài 1998.
Yêu cầu Lua 5.2

Làm thế nào chương trình Lua tùy ý có thể được viết chỉ bằng 8 ký tự load"\05

Có ký tự 05\, có thể viết chuỗi ký tự cho bất kỳ chuỗi bao gồm ký tự 0257\. Thật vậy, "\\"có nghĩa là dấu gạch chéo ngược "2" == "\50" và "7" == "\55"( "\ddd"trong Lua có nghĩa là char với mã thập phân ddd).
Có ký tự 0257\, có thể viết chuỗi ký tự cho bất kỳ chuỗi nào bao gồm ký tự 024579\(như "4" == "\52"và "9" == "\57")
Trên bước tiếp theo ký tự01245679\ sẽ có sẵn.
Một bước nữa là cần thiết để có được tất cả các chữ số thập phân.

Lua có chức năng loadcoi một chuỗi là mã Lua và chuyển đổi nó thành một hàm.
Ví dụ, load("print\"Hello\"")()in Hello.
Nó có thể được viết mà không có dấu ngoặc đơn: load"print\"Hello\""""(hai dấu ngoặc kép có nghĩa là chuỗi rỗng được truyền dưới dạng tham số tùy chọn cho hàm).
Bất kỳ chương trình Lua nào cũng có thể được chuyển đổi thành bảng chữ cái rút gọn trong tối đa 5 bước.
Ví dụ: Nếu chương trình của chúng tôi bao gồm một chữ số 9, thì chỉ cần hai bước:
bước 0: 9
bước 1: load"\57"""
bước 2: load"load\"\\5\55\"\"\""""

— Egor Skriptunoff
nguồn
14

Con trăn, 9

Sử dụng ý tưởng này . (Các ngắt dòng ở đó để dễ đọc và có thể được gỡ bỏ.)

exec(chr(111+1)+chr(111+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1)+chr(11
+11+11+11+11+11+11+11+11+11)+chr(111+1+1+1+1+1)+chr(11+11+11+1)+chr(11+11+11+11
+11+11+11+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)+chr(11+11+11+
11+11+11+11+11+11+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1+1)+chr(111+1+1)+chr(111+1+1+1
+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+
11)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1+
1)+chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)+chr(111+1+1+1)+chr(111)+chr(
111+1+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+11)+chr(11+11+1+1+1+1+1+1+1+
1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1)+chr(111)+chr(111+1+1+1+1+1+1+1+1+1)
+chr(11+11+1+1+1+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1)+chr
(111+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)+chr(111+1
)+chr(111+1+1+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1+1)+chr(111)+chr(111+1+1+1+1+1+1+1
)+chr(11+11+11+11+11+11+11+11+11+1+1)+chr(111+1+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1
+1)+chr(111+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)+chr(11+11+11+11
+11+11+11+11+11+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+
11+1+1+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1)+chr(111+11)
+chr(111+1+1+1+1+1+1+1+1+1+1)+chr(11+11+1+1+1+1+1+1+1+1+1+1)+chr(11+11+11+11+11+
11+11+11+11+1)+chr(111)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1)+chr(11+11+11+1))

Điều này xây dựng chuỗi 'print"The quick brown fox jumps over the lazy dog"'và thực hiện nó.

— flornquake
nguồn
Thách thức là in cụm từ, không viết chương trình. Tôi nghĩ bạn có thể loại bỏ exec, nói rằng bạn chạy nó trên vỏ trăn và yêu cầu 7 ký tự.
— Griffin
12
Sử dụng 11 và 111 cũng làm cho nó ngắn hơn và thanh lịch thanh lịch.
— Randomra
4
"dễ đọc" - heh.
@Griffin, chỉ cần tạo chuỗi thay vì xuất ra nó sẽ thay đổi thử thách quá nhiều. Ví dụ: giải pháp Ruby sẽ chỉ mất 4 ký tự.
— manatwork
@randomra: Điểm tốt, điều đó làm cho nó ngắn hơn rất nhiều.
— flornquake
8

dc - 5 ký tự riêng biệt (2, i, 1,0, P)

2i01010100011010000110010100100000011100010111010101101001011000110110101100100000011000100111001001101111011101110110111000100000011001100110111101111000001000000110101001110101011011010111000001110011001000000110111101110110011001010111001000100000011101000110100001100101001000000110110001100001011110100111100100100000011001000110111101100111P
— Geoff Sậy
nguồn
7

Tcl 10 ký tự khác nhau.

\160\165\164\163 \124\150\145\40\161\165\151\143\153\40\142\162\157\167\156\40\146\157\170\40\152\165\155\160\163\40\157\166\145\162\40\164\150\145\40\154\141\172\171\40\144\157\147

Nhân vật sử dụng: , 0, 1, 2, 3, 4, 5, 6, 7,\

Đó chỉ là mỗi phần của lệnh được mã hóa dưới dạng chuỗi \ ooo. Đối với Tcl, không có vấn đề gì nếu bạn làm những điều buồn cười như vậy trong tên lệnh hoặc trong các đối số của anh ta, trên thực tế, điều $object configurenày rất phổ biến trong Tcl / Tk.
Với kỹ thuật này và evalbạn thậm chí có thể viết mọi chương trình trong Tcl với 10 byte khác nhau :)

Chương trình kiểm tra:

set code [read stdin]
puts "Characters used: `[join [set ch [lsort -unique [split $code {}]]] {`, `}]`
puts "Number of different characters: [llength $ch]"
— Julian Kuhn
nguồn
1
+1. Một thủ thuật tương tự hoạt động trong Java với \uXXXX18 byte khác nhau.
— Peter Taylor
7

GolfScript (4 ký tự riêng biệt, tổng số 441 ký tự)

11(11+11+11+11+11+11+11+(((111(((((((111((((((((((11(11+11+111(1+1+1+111(11+((((111((((((111((((((((((((111((((11(11+11+111(((((((((((((111(1+1+1+1+111(1+111(11+((111(11(11+11+111(((((((((111(1+111(11+(11(11+11+111(((((111(11+((((111((111(1+1+111(11+((((((11(11+11+111(1+111(11+(((111((((((((((111(1+1+1+1+11(11+11+111(11+(((((111(((((((111((((((((((11(11+11+111(((111((((((((((((((111(11+1+111(11+11(11+11+111(((((((((((111(1+111((((((((](+

Chars sử dụng: ]1(+

Giải thích: trong GolfScript, việc thêm một chuỗi vào một mảng các số nguyên sẽ chuyển đổi mảng thành một chuỗi với các số nguyên dưới dạng mã hóa và sau đó nối hai chuỗi. Nếu không có gì được cung cấp trên stdin, ngăn xếp bắt đầu bằng một chuỗi rỗng. Vì vậy, chúng ta có thể xây dựng một mảng các số nguyên với các điểm mã đúng và sau đó nối với chuỗi trống đó.

Chúng ta sẽ cần +kết nối, ]tối thiểu để tạo mảng (và [để ngăn chặn chuỗi trống được đưa vào trong đó hoặc một số cách trích xuất sau đó) và một số cách để tách các số nguyên. Vì vậy, tôi sử dụng toán tử giảm (dần để tách các số nguyên, đòi hỏi một số bổ sung bổ sung để bù vào một số trường hợp nhưng đưa ra cách nhanh chóng để lấy ví dụ 110; và toán tử đó cũng là toán tử để trích xuất phần tử đầu tiên từ một mảng, do đó, nó phục vụ để lấy chuỗi rỗng để nối.

— Peter Taylor
nguồn
Vì bạn và Fors hiện đang bị ràng buộc với 4 ký tự, mỗi ký tự, tôi đã cập nhật các quy tắc để nói rằng nếu đó vẫn là một ràng buộc khi thời hạn đến, tôi sẽ chấp nhận câu trả lời ngắn hơn. Câu trả lời của bạn ngắn hơn đáng kể vào lúc này, nhưng sẽ không công bằng khi tôi thông báo cho anh ấy chứ không phải bạn. :)
— Fraxtil
6

Ruby: 7 ký tự riêng biệt

(Cảm ơn ngẫu nhiên vì bình luận của anh ấy .)

$>.<<""<<11+11+11+11+11+11+11+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<111+1+1<<111+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1<<111+1+1+1<<111<<111+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+11<<11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1<<111<<111+1+1+1+1+1+1+1+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1<<111+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1<<111+1<<111+1+1+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<111<<111+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1<<111+1+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<111+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<111+11<<111+1+1+1+1+1+1+1+1+1+1<<11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1<<111<<11+11+11+11+11+11+11+11+11+1+1+1+1

Chạy mẫu:

bash-4.2$ ruby distinctchar.rb
The quick brown fox jumps over the lazy dog

Đếm:

bash-4.2$ sed 's/./&\n/g' distinctchar.rb | sort -u | wc -l
7

bash-4.2$ sed 's/./&\n/g' distinctchar.rb | sort | uniq -c
     88 <
      1 >
      1 .
      2 "
      1 $
    384 +
    637 1
— chế tạo
nguồn
5

Java: 18 ký tự riêng biệt

\u0063\u006C\u0061\u0073\u0073\u0020\u0054\u007B\u0070\u0075\u0062\u006C\u0069\u0063\u0020\u0073\u0074\u0061\u0074\u0069\u0063\u0020\u0076\u006F\u0069\u0064\u0020\u006D\u0061\u0069\u006E\u0028\u0053\u0074\u0072\u0069\u006E\u0067\u005B\u005D\u0020\u0061\u0029\u007B\u0053\u0079\u0073\u0074\u0065\u006D\u002E\u006F\u0075\u0074\u002E\u0070\u0072\u0069\u006E\u0074\u006C\u006E\u0028\u0022\u0054\u0068\u0065\u0020\u0071\u0075\u0069\u0063\u006B\u0020\u0062\u0072\u006F\u0077\u006E\u0020\u0066\u006F\u0078\u0020\u006A\u0075\u006D\u0070\u0073\u0020\u006F\u0076\u0065\u0072\u0020\u0074\u0068\u0065\u0020\u006C\u0061\u007A\u0079\u0020\u0064\u006F\u0067\u0022\u0029\u003B\u007D\u007D

Một chương trình Java có thể được viết bằng ký hiệu UNC ... Nhưng nó vẫn dài dòng!

— PhiLho
nguồn
5

J, 6 ký tự riêng biệt

6 phiên bản char riêng biệt ( u:10 +) sử dụng một số ý tưởng flornquake được sử dụng. Phương pháp này là thêm các vectơ của 0 1 11và 111cùng nhau để thêm vào 84 104 101 32 113 117 ...vectơ mong muốn :

   u:11 11 11 11 111 111 11 11 11 11 11 111 111 111 11 11 11 111 111 11 11 111 11 111 111 11 111 111 11 111 11 111 11 11 11 11 11 111 111 11 11 111 11 + 11 11 11 11   1   1 11 11 11 11 11   1   0   1 11 11 11   0   1 11 11   1 11   1   1 11   0   1 11   1 11   1 11 11 11 11 11  11   1 11 11   0 11 + 11 11 11  1   1   1 11 11 11  1 11   1   0   1 11  1 11   0   1  1 11   1 11   0   1  1   0   1 11   1  1   1 11 11  1 11 11   0   1  1 11   0 11 + 11 11 11  1   0   1 11 11 11  1 11   1   0   1 11  1 11   0   1  1 11   1 11   0   1  1   0   1 11   1  1   1 11 11  1 11 11   0   1  1 11   0 11 + 11 11 11  1   0   1 11 11 11  1 11   0   0   1 11  1 11   0   1  1 11   1 11   0   1  1   0   1 11   0  1   1 11 11  1 11 11   0   1  1 11   0 11 + 11 11 11  1   0   1 11 11 11  1 11   0   0   1 11  1 11   0   1  1 11   1 11   0   0  1   0   1 11   0  1   1 11 11  1 11 11   0   1  1 11   0 11 + 11 11 11  1   0   1 11 11 11  1 11   0   0   1 11  1 11   0   1  1 11   1 11   0   0  1   0   1 11   0  1   0 11 11  1 11 11   0   1  1 11   0 11 +  1 11 11  1   0   0 11 11 11  1 11   0   0   1 11  1 11   0   1  1 11   0 11   0   0  1   0   1 11   0  1   0 11 11  1 11 11   0   1  1 11   0 11 +  1 11 11  1   0   0 11 11 11  1  1   0   0   1 11  1 11   0   1  1 11   0 11   0   0  1   0   0 11   0  1   0 11 11  1 11  1   0   1  1 11   0 11 +  1  1  1  1   0   0  1  0  1  1  1   0   0   0 11  1  1   0   1  1  1   0  1   0   0  1   0   0  1   0  1   0  1  1  1  1  1   0   1  1  1   0  1 +  1  1  1  1   0   0  1  0  1  1  1   0   0   0  0  1  1   0   0  1  1   0  1   0   0  1   0   0  1   0  1   0  1  1  1  1  1   0   1  1  0   0  1 +  1  1  0  1   0   0  1  0  1  1  1   0   0   0  0  1  1   0   0  1  1   0  1   0   0  1   0   0  0   0  1   0  1  0  1  1  1   0   0  1  0   0  1 +  1  1  0  0   0   0  1  0  1  0  1   0   0   0  0  0  0   0   0  0  1   0  1   0   0  0   0   0  0   0  0   0  1  0  0  1  1   0   0  0  0   0  1 +  1  1  0  0   0   0  1  0  1  0  1   0   0   0  0  0  0   0   0  0  1   0  1   0   0  0   0   0  0   0  0   0  1  0  0  1  1   0   0  0  0   0  0 +  0  0  0  0   0   0  1  0  1  0  1   0   0   0  0  0  0   0   0  0  1   0  1   0   0  0   0   0  0   0  0   0  0  0  0  1  1   0   0  0  0   0  0 +  0  0  0  0   0   0  0  0  1  0  1   0   0   0  0  0  0   0   0  0  1   0  1   0   0  0   0   0  0   0  0   0  0  0  0  1  1   0   0  0  0   0  0 +  0  0  0  0   0   0  0  0  1  0  1   0   0   0  0  0  0   0   0  0  0   0  1   0   0  0   0   0  0   0  0   0  0  0  0  1  1   0   0  0  0   0  0 +  0  0  0  0   0   0  0  0  0  0  1   0   0   0  0  0  0   0   0  0  0   0  1   0   0  0   0   0  0   0  0   0  0  0  0  1  0   0   0  0  0   0  0 +  0  0  0  0   0   0  0  0  0  0  0   0   0   0  0  0  0   0   0  0  0   0  1   0   0  0   0   0  0   0  0   0  0  0  0  0  0   0   0  0  0   0  0
The quick brown fox jumps over the lazy dog

Chỉnh sửa : 1+:1được 0như vậy có lẽ có một giải pháp 5 char ở đây ... (Cũng +:như đôi có thể được sử dụng để rút ngắn các giải pháp.)

13 phiên bản char riêng biệt:

   u: 84 104 101 32 113 117 105 99 107 32 98 114 111 119 110 32 102 111 120 32 106 117 109 112 115 32 111 118 101 114 32 116 104 101 32 108 97 122 121 32 100 111 103
The quick brown fox jumps over the lazy dog

Cải thiện người dùng ẩn danh (DirkL): giải pháp ngắn hơn nhưng vẫn sử dụng 6 ký tự ( u:23 |) là có thể. Sử dụng |như toán tử dư cho số thập phân, ví dụ 223 | 2333333 = 84.

   u:223|2333333 232333323 3223 32 23223333 23222222 323232 322 32333323 32 322333 232333333 3233 2323333 3232 32 2332 3233 32232 32 323233 23222222 2323323 23223332 3223333322 32 3233 2323332 3223 232333333 32 32333332 232333323 3223 32 2323322 322332 32332223 32233 32 323 3233 2333
The quick brown fox jumps over the lazy dog
— ngẫu nhiên
nguồn
Bạn nên kết hợp giải pháp 7 char với gợi ý của Randomra để sử dụng 111 và 11 nếu có thể.
— Fraxtil
@Fraxtil Tôi là ngẫu nhiên. :) Tôi đã làm nó bây giờ. Tôi cũng có thể sử dụng 10 100 và 101 bây giờ, nhưng tôi sẽ bỏ qua điều đó.
— Randomra
Haha, rất tiếc Công việc tốt dù sao.
— Fraxtil
5

Befunge-98, 3 ký tự riêng biệt

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Sử dụng này Befunge-98 thông dịch viên. Lúc đầu, tôi tham gia cuộc thi 4 nhân vật với một @kết thúc để chấm dứt. Chương trình này liên tục xuất ra The quick brown fox jumps over the lazy dog\r, khi kết thúc\r xóa câu trước đó. Do đó, câu được viết một lần.


Befunge-98, 4 ký tự riêng biệt (tổng cộng 1047 ký tự)

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Các phiên bản ít gian lận hơn. Điều này chấm dứt bình thường.

— bản sao
nguồn
@ dan1111 Nguồn không chứa ngắt dòng, hãy để tôi làm rõ điều đó
— sao chép
4

JavaScript (trong Bảng điều khiển Chrome) 17

Tôi có cùng ý tưởng với flornquake nhưng anh ấy cũng đánh tôi. Vì vậy, tôi đã đi cho cách xấu xí để làm điều này!

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— Griffin
nguồn
6
Phe nhanh bro n cáo không xác định trên con chó lười?
— Nỗi sợ hãi tuyệt vọng
2
Ah, tôi đoán những gì bạn nhận constructor+[]được khác với những gì tôi nhận được. Phiên bản chrome khác nhau tôi giả sử. Nói với bạn rằng nó thật xấu xí
— Griffin
1
Việc đưa nó vào bảng điều khiển của Fireorms trên Firefox rất thú vị - chỉ "nhanh" và "cáo" xuất hiện chính xác. Đoán rằng các tác phẩm được đặt tên của trình duyệt;)
— Izkata
4

C, 15 ký tự riêng biệt

Một số cảm hứng từ câu trả lời của Fors (mà tôi đánh bại bởi một nhân vật) và nhận xét của ecatmur cho câu trả lời đó.
Không gian và dòng mới chỉ cho rõ ràng, và không được tính.

Làm thế nào nó hoạt động?
1. Mỗi nhóm gồm 3 ký tự được thể hiện bằng một số. Một con trỏ tới số này, được coi là một con trỏ ký tự, là một con trỏ tới một chuỗi gồm 3 ký tự này, cộng với một null kết thúc. Giả sử ít endian.
2. Hàm agiúp lấy địa chỉ của một số bằng chữ mà không cần xác định biến.

a(i){if(printf(&i)){}}
main(){
    if(a(1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+11111+11111+11111+11111+1111+111+111+11+11+11+11+11+11+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+111111+111111+111111+111111+11111+11111+1111+1111+1111+1111+1111+1111+1111+1+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+11111+11111+11111+1111+1111+1111+1111+11+11+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+1111+1111+1111+1111+1111+1111+111+111+111+111+111+111+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+11111+1111+1111+1111+1111+1111+111+111+111+111+111+11+11+11+11+11+11+11+11+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+11111+11111+11111+111+111+111+111+111+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+11111+11111+11111+11111+11111+1111+1111+1111+1111+1111+1111+1111+1111+1111+111+111+111+111+111+111+11+1+1+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+111111+11111+11111+11111+1111+111+111+11+11+11+11+11)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+11111+1111+1111+1111+1111+111+111+111+111+111+11+11+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+1111+1111+1111+1111+1111+1111+1111+111+111+111+11+11+11+11+11+11+11+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+11111+11111+11111+11111+11111+11111+111+111+111+111+111+111+111+111+111+11+11+1+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+11111+11111+11111+11111+11111+11111+11111+1111+1111+1111+1111+1111+1111+1111+111+111+111+111+111+11+11+11+11+11+11+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+1111111+111111+11111+11111+11111+11111+11111+11111+1111+1111+1111+1111+1111+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)){}
    if(a(1111111+1111111+1111111+1111111+1111111+1111111+111111+111111+111111+111111+111111+11111+11111+11111+11111+11111+11111+11111+111+11+1+1+1+1+1+1+1+1)){}
    if(a(1111+1111+111+111+111+11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1)){}
}
— xấu xí
nguồn
Tốt đẹp! Thật không may, nó in "Con cáo nâu nhanh chóng nhảy qua con chó thazy" đối với tôi bằng Clang / GCC / ICC trong Mac OS X. Và dưới Linux (một máy ảo có Arch), nó in chuỗi chính xác bằng GCC và chuỗi thazy sử dụng Clang. Vì Clang thường đúng hơn và tuân thủ các tiêu chuẩn, dường như có điều gì đó kỳ lạ đang diễn ra.
— Dành cho
Nó cũng in chuỗi thazy bằng GCC với tối ưu hóa trong Linux.
— Dành cho
1
@fors, Đã sửa. Đó là một thiếu sót {}trong một trong những dòng, khiến nó nhạy cảm với agiá trị trả về của nó.
— ugoren
3

vba ( 16 8 ký tự riêng biệt)

(sử dụng ý tưởng từ matatwork và AutomatedChaos)

?Chr(11+11+11+11+11+11+11+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(111+1+1)Chr(111+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)Chr(111+1+1+1)Chr(111)Chr(111+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+11)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1)Chr(111)Chr(111+1+1+1+1+1+1+1+1+1)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1)Chr(111+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1)Chr(111+1)Chr(111+1+1+1+1)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(111)Chr(111+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1)Chr(111+11)Chr(111+1+1+1+1+1+1+1+1+1+1)Chr(11+11+1+1+1+1+1+1+1+1+1+1)Chr(11+11+11+11+11+11+11+11+11+1)Chr(111)Chr(11+11+11+11+11+11+11+11+11+1+1+1+1)

lưu ý rằng nếu bạn muốn đặt cái này vào, bạn sẽ phải chia dòng thành 2, vì nó quá dài cho trình soạn thảo VBA

Mã: 40 '(' Đếm: 37
Mã: 41 ')' Đếm: 37
Mã: 43 '+' Đếm: 331
Mã: 49 '1' Đếm: 552
Mã: 63 '?' Đếm: 1
Mã: 67 'C' Đếm: 37
Mã: 104 'h' Đếm: 37
Mã: 114 'r' Đếm: 37
----- TỔNG ĐẶC ĐIỂM: 1069

— SeanC
nguồn
Tại sao sử dụng tham số chuỗi cho Chr()? Có vẻ hoạt động tốt mà không cần : ?Chr(&0124);Chr(&0150);Chr(&0145);….
— manatwork
@manatwork, đã sửa, cảm ơn bạn
— SeanC
1
Theo phương pháp của bạn, bạn có thể thực hiện thành 8 ký tự riêng biệt: ?chr(1+)nó sẽ giống như?chr(11+11+11+11+11+11+11+1+1+1+1+1+1+1)+chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)+ .... etc.
— AutomatedChaos
Đã thử nghiệm thêm một số trong VBA 7.1 (phiên bản đi kèm với Office 2013) và cũng không cần phải có dấu chấm phẩy : ?Chr(&0124)Chr(&0150)Chr(&0145)….
— manatwork
2

C: 16 ký tự riêng biệt

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a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a+a);putchar(a+a+a+a+a+a+a+a+a+a);}
— Fors
nguồn
Biến thể có cùng độ dài - if(putchar(...)+putchar(...)){}loại bỏ ;nhưng thêm f(nhưng phụ thuộc vào thứ tự đánh giá không xác định).
— ugoren
@ugoren bạn có thể sửa thứ tự đánh giá với if(putchar(...)){}if(putchar(...)){}vv
— ecatmur
@ecatmur, thực sự hoạt động. Cũng if(putchar(...))if(putchar(...)){}hay if(putchar(putchar(...)+...){}, nhưng vẫn tiếp cận này không lưu lại một ký tự.
— ugoren
2

Phần tái bút (19 ký tự riêng biệt)

<54686520717569636b2062726f776e20666f78206a756d7073206f76657220746865206c617a7920646f67>=

Sử dụng các chữ số thập lục phân 0-9, af, dấu phân cách chuỗi hex <> và = để in.

(13 ký tự riêng biệt)

( )dup 0 2#1010100 put dup print dup 0
2#1101000 put dup print dup 0
2#1100101 put dup print dup 0
2#100000 put dup print dup 0
2#1110001 put dup print dup 0
2#1110101 put dup print dup 0
2#1101001 put dup print dup 0
2#1100011 put dup print dup 0
2#1101011 put dup print dup 0
2#100000 put dup print dup 0
2#1100010 put dup print dup 0
2#1110010 put dup print dup 0
2#1101111 put dup print dup 0
2#1110111 put dup print dup 0
2#1101110 put dup print dup 0
2#100000 put dup print dup 0
2#1100110 put dup print dup 0
2#1101111 put dup print dup 0
2#1111000 put dup print dup 0
2#100000 put dup print dup 0
2#1101010 put dup print dup 0
2#1110101 put dup print dup 0
2#1101101 put dup print dup 0
2#1110000 put dup print dup 0
2#1110011 put dup print dup 0
2#100000 put dup print dup 0
2#1101111 put dup print dup 0
2#1110110 put dup print dup 0
2#1100101 put dup print dup 0
2#1110010 put dup print dup 0
2#100000 put dup print dup 0
2#1110100 put dup print dup 0
2#1101000 put dup print dup 0
2#1100101 put dup print dup 0
2#100000 put dup print dup 0
2#1101100 put dup print dup 0
2#1100001 put dup print dup 0
2#1111010 put dup print dup 0
2#1111001 put dup print dup 0
2#100000 put dup print dup 0
2#1100100 put dup print dup 0
2#1101111 put dup print dup 0
2#1100111 put dup print dup 0

%   1 2 3 4 5 6 7 8 9 0 1 2 3
%   0 1 2 # d i u n p r t ( )

Các số cơ số nhị phân lấy dữ liệu trong 4 ký tự (0,1,2, #), nhưng nó cần một chuỗi trống () và một số chữ cái (đặt, dup (-up), in (-pt)) để chèn số nhị phân trong đó.

— kẻ lừa đảo
nguồn
2

APL 8

Lệnh sau chuyển đổi một chuỗi ký tự thành tương đương nhị phân của nó:

s←11 ⎕dr "The quick brown fox jumps over the lazy dog"

Nếu chúng ta gán nhị phân kết quả cho các vectơ để tránh phải hiển thị tất cả các số 0 và số 0 thì chúng ta có thể in kết quả bằng cách đảo ngược quá trình bằng cách áp dụng:

82 ⎕dr s

"The quick brown fox jumps over the lazy dog"

Vậy 8 ký tự duy nhất là 8.2, ⎕, d, r, dấu cách và 0 và 1 trong vectơ nhị phân s.

— Graham
nguồn
2

k

12 nhân vật riêng biệt

1'10h$2/:'(01010100b;01101000b;01100101b;00100000b;01110001b;01110101b;01101001b;01100011b;01101011b;00100000b;01100010b;01110010b;01101111b;01110111b;01101110b;00100000b;01100110b;01101111b;01111000b;00100000b;01101010b;01110101b;01101101b;01110000b;01110011b;00100000b;01101111b;01110110b;01100101b;01110010b;00100000b;01110100b;01101000b;01100101b;00100000b;01101100b;01100001b;01111010b;01111001b;00100000b;01100100b;01101111b;01100111b);

Các nhân vật là 10h$2/:'(b;)

— hoài nghi
nguồn
2

PHP. 10 nhân vật riêng biệt.

e, c, h, o, r, (, 1, +, ), ; (Ngắt dòng có thể được gỡ bỏ.)

echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(111));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(111));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(111+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(111));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
echo(chr(111));
echo(chr(1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1));
— Adam Balsam
nguồn
Bạn đã quên đếm 'r', vì vậy tôi đếm 11 ký tự riêng biệt.
— Zombaya
4
Và tôi nghĩ rằng bạn có thể mất dung lượng bằng cách sử dụng echo(chr(1+1+1+...));, vì vậy bạn quay lại 10 ký tự một lần nữa.
— Zombaya
1

Bash: 18 16 ký tự riêng biệt

printf `printf \\\\\\\\x%x $[11+11+11+11+11+11+11+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[111+1+1] $[111+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1] $[111+1+1+1] $[111] $[111+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+11] $[11+11+1+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1] $[111] $[111+1+1+1+1+1+1+1+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1] $[111+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1] $[111+1] $[111+1+1+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[111] $[111+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1] $[111+1+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[111+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1] $[111+11] $[111+1+1+1+1+1+1+1+1+1+1] $[11+11+1+1+1+1+1+1+1+1+1+1] $[11+11+11+11+11+11+11+11+11+1] $[111] $[11+11+11+11+11+11+11+11+11+1+1+1+1]`

Chạy mẫu:

bash-4.2$ bash distinctchar.sh 
The quick brown fox jumps over the lazy dog

Đếm:

bash-4.2$ sed 's/./&\n/g' distinctchar.sh | sort -u | wc -l
16

bash-4.2$ sed 's/./&\n/g' distinctchar.sh | sort | uniq -c
      2 `
     45  
     43 [
     43 ]
     43 $
      8 \
      1 %
    384 +
    637 1
      2 f
      2 i
      2 n
      2 p
      2 r
      2 t
      2 x
— chế tạo
nguồn
Có lẽ nó bẻ cong các quy tắc, nhưng catchỉ là một giải pháp 3 ký tự. Điều hấp dẫn là bạn cần phải luồn "The quick brown fox jumps over the lazy dog"vào đó.
— Ông Llama
@GigaWatt, thú vị. Nhưng điều gì sẽ chuyển đổi mã ký tự thành ký tự?
— manatwork
1

K, 9

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1 @ 0 h $ (+;)

— tmartin
nguồn
1

Perl, 10 ký tự

Về cơ bản là sự lột xác của giải pháp Python của flornquake.

Sử dụng thay thế bằng eelà một cách rẻ hơn để có được eval. Thật không may, Perl sử dụng. để ghép nối, thêm một ký tự.

Tôi đã hy vọng loại bỏ dấu ngoặc đơn (tùy chọn cho các hàm trong Perl), sử dụng cú pháp như sau:

s ss char 111+1 ... see

(Có, slà một dấu phân cách regex hợp lệ). Tuy nhiên, tôi không thể làm cho nó hoạt động được vì mức độ ưu tiên .quá cao, cố gắng nối lại trước khi nó gọi hàm.

s()(chr(111+1).chr(111+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1).chr(
11+11+11+11+11+11+11+11+11+11).chr(111+1+1+1+1+1).chr(11+11+11+1).chr(11+11+11+
11+11+11+11+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1).chr(11+11+
11+11+11+11+11+11+11+1+1).chr(11+11+1+1+1+1+1+1+1+1+1+1).chr(111+1+1).chr(111+1
+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1).chr(11+11+11+11+11+11+
11+11+11).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1).chr(11+11+1+1+1+1+1+1
+1+1+1+1).chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1).chr(111+1+1+1).chr(
111).chr(111+1+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+11).chr(11+11+1+1+
1+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1).chr(111).chr(111+1+1+1+1
+1+1+1+1+1).chr(11+11+1+1+1+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1
+1+1+1+1).chr(111+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1
+1).chr(111+1).chr(111+1+1+1+1).chr(11+11+1+1+1+1+1+1+1+1+1+1).chr(111).chr(111
+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1).chr(111+1+1+1).chr(11+11+1+
1+1+1+1+1+1+1+1+1).chr(111+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+11+1+1+1+1+1)
.chr(11+11+11+11+11+11+11+11+11+1+1).chr(11+11+1+1+1+1+1+1+1+1+1+1).chr(11+11+
11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1).chr(11+11+11+11+11+11+11+11+1+1+1+1+1+1
+1+1+1).chr(111+11).chr(111+1+1+1+1+1+1+1+1+1+1).chr(11+11+1+1+1+1+1+1+1+1+1+1)
.chr(11+11+11+11+11+11+11+11+11+1).chr(111).chr(11+11+11+11+11+11+11+11+11+1+
1+1+1).chr(11+11+11+1))ee
1

Erlang 8 ký tự riêng biệt

Ký tự được sử dụng: 012#<>:.

<<2#1010100011010000110010100100000011100010111010101101001011000110110101100100000011000100111001001101111011101110110111000100000011001100110111101111000001000000110101001110101011011010111000001110011001000000110111101110110011001010111001000100000011101000110100001100101001000000110110001100001011110100111100100100000011001000110111101100111:2#101011000>>.
— Hynek -Pichi- Vychodil
nguồn
1

C (23 ký tự riêng biệt)

main(){
puts("\124\150\145\040\161\165\151\143\153\040\142\162\157\167\156\040"
"\146\157\170\040\152\165\155\160\163\040\157\166\145\162\040\164"
"\150\145\040\154\141\172\171\040\144\157\147");
}

Lưu ý: Tôi không bao gồm các dòng mới trong số lượng ký tự riêng biệt, nhưng chúng có thể dễ dàng được loại bỏ nếu cần, với chi phí dễ đọc.

— Paul R
nguồn
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